// 计算字符串中的字符个数的函数
#include <stdio.h>

int stringLength(const char string[]){
	int count = 0;
		
	while(string[count] != '\0')
		++count;
	
	return count;
}

int main(void){
	int stringLength(const char string[]);
	const char word1[] = {'a', 's', 't', 'e', 'r', '\0'};
	const char word2[] = {'a', 't', '\0'};
	const char word3[] = {'a', 'w', 'e', '\0'};
	
	printf("%i %i %i\n", stringLength(word1),
				stringLength(word2), stringLength(word3));
				
	return 0;
}
